Reciprocal Graphs Sketch And Hence Find The Reciprocal Graph Y 0 Y 1 Y 2 Y 1 2 Y 3 Y 1 3 X 1 Y 0 Hyperbola Asymptote Domain X R 1 Ppt Download
Axis\\frac{(y3)^2}{25}\frac{(x2)^2}{9}=1 foci\4x^29y^248x72y108=0 vertices\x^2y^2=1 eccentricity\x^2y^2=1 asymptotes\x^2y^2=1 hyperbolaequationcalculator eccentricity x^2y^2=1 en So, by Pythagoras $2(x^2y^2)=4y^2$, or $x=y$ Putting this on the equation of the hyperbola we get that $x=\frac{ab}{\sqrt{b^2a^2}}$ This value of $x$ is how far the vertical chord is from the origin and therefore it is the radius of the circle $\endgroup$
